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How to teach the area of triangles and parallelograms

Year 7 (ages 12 to 13)

Quick answer

The area formulas for triangles (1/2 x base x height) and parallelograms (base x height) both come from the area of a rectangle. This unit covers applying both formulas and finding a missing dimension when the area is already known.

How to teach it

  1. Show why a parallelogram's area equals base x height by cutting and rearranging it into a rectangle.
  2. Show why a triangle's area is HALF of base x height by fitting two identical triangles together to make a parallelogram.
  3. Practise identifying the base and the PERPENDICULAR height in a diagram, since the height is not always a drawn side.
  4. Solve for a missing base or height by rearranging the formula (dividing the area by the known dimension) once the standard direction is secure.
  5. Mix triangle and parallelogram problems together so students practise choosing the right formula each time.

Worked example

Find the area of a triangle with base 10 and height 6
1/2 x 10 x 6 = 30 square units

Common mistakes

Frequently asked questions

What is the formula for the area of a triangle?

Area = 1/2 x base x height. A triangle with base 8 and height 5 has area 1/2 x 8 x 5 = 20 square units.

What is the formula for the area of a parallelogram?

Area = base x height (the same as a rectangle, since a parallelogram can be rearranged into a rectangle of the same base and height).

How do you find a missing base or height if you know the area?

Divide the area by the known dimension. If a parallelogram has area 40 and height 8, its base is 40 / 8 = 5.

What year is the area of triangles and parallelograms taught?

In the Australian Curriculum this is a Year 7 skill (AC9M7M01): using established formulas and suitable units to solve problems about the area of triangles and parallelograms.

Practise with free worksheets

Printable worksheets with answer keys that are never wrong.

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